When 3,3-dichloropentane is treated with excess sodium a
Question and Solution
When 3,3-dichloropentane is treated with excess sodium amide in liquid ammonia, the initial product is 2-pentyne: Howeve
64 % (208 Review)
When 3,3-dichloropentane is treated with excess sodium amide in liquid ammonia, the initial product is 2-pentyne: However, under these conditions, this internal alkyne quickly isomerizes to form a terminal alkyne that is subsequently deprotonated to form an alkynide ion: The isomerization process is believed to occur via a mechanism with the following four steps: (1) deprotonate, (2) protonate, (3) deprotonate, and (4) protonate. Using these four steps as a guide, try to draw the mechanism for isomerization using resonance structures whenever possible. Explain why the equilibrium favors formation of the terminal alkyne.
Your answer will be ready within 2-4 hrs. Meanwhile, check out other millions of Q&As and Solutions Manual we have in our catalog.
Get immediate access to 24/7 Homework Help, step-by-step solutions, instant homework answer to over 40 million Textbook solution and Q/A
Pay $7.00/month for Better Grades
Crazy for Study is a platform for the provision of academic help. It functions with the help of a team of ingenious subject matter experts and academic writers who provide textbook solutions to all your course-specific textbook problems, provide help with your assignments and solve all your academic queries in the minimum possible time.
Disclaimer: Crazy For Study provides academic assistance to students so that they can complete their college assignments and projects on time. We strictly do not deliver the reference papers. This is just to make you understand and used for the analysis and reference purposes only.