Example 3 showed that the method of Lagrange multipliers mig
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Example 3 showed that the method of Lagrange multipliers might fail to find a point that extremizes f .x; y/ subject to
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Example 3 showed that the method of Lagrange multipliers might fail to find a point that extremizes f .x; y/ subject to the constraint g.x; y/ D 0 if rg D 0 at the extremizing point. Can the method also fail if rf D 0 at the extremizing point? Why?
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